| ToC, Chapter 12 | Course Calendar |
D12.1 Calculate the mass of Jupiter, given that its moon
Callisto has a mean orbital radius of 1.88 x 106
km and an orbital period of 16 days, 16.54 hours.
The force of gravity provides the centripetal force to keep Callisto
in its orbit.
We must find the linear speed of Callisto.
T = 16 d, 16.54 h = [(16)(24) + 16.54 ]
h = 400.54 h
T = 400.54 h [3600 s/h]
= 1.44 x 106 s
Fgravity = Fcentripetal
Fgravity = G MJ mC/r2 = mC v2/r = Fcentripetal
G MJ mC/r2 = mC v2/r
MJ = r v2/G
MJ
= 1.9 x 1027 kg
D12.2 Starting with the moon's period of 27.3 days,
calculate the radius of its orbit.
The gravitational force between Earth and our moon provides the centripetal
force,
Dont try to solve for the radius
immediately for we know the velocity only in terms of the radius,
= m = m
T = 27.3 da (24 h/da) (3600 s/h) = 2.36 x
106
s
r3
=
r3
=
r3
= 5.627 x
1025
m3
r = 3.83 x
108
m
r = 3.83 x
105
km
D12.3 The acceleration of a falling body near Earths surface, at a distance R from Earths center, is 9.80 m/s2.
(a) Use a suitable proportion to calculate the acceleration toward Earth of a falling body that is 60 R from Earths center.
(b) Our moon is in an orbit of radius 60 R, with a period of revolution of 27.26 days. Show, as did Sir Isaac Newton, that the centripetal acceleration of the moon toward Earth agrees with your answer from part (a).
Earths radius is R = 6.38 x 103 km.
D12.4 What orbital radius should a weather satellite have if it is to have a period of 6.0 hours?
r = 1.68 x 10 7 m = 1.68 x 10 4 km = 16,800 km
D12.5 From the data below, calculate the acceleration of free fall on the surface of
a) Jupiter,
b) Saturn, and
c) our Moon.
mass radius Jupiter 1 900 x 10^24 kg 71 400 kmSaturn
561 x 10^24 kg 60 000 km moon 0.0736 x 10^24 kg 1 740 kmF = m a = G
a)b)
c)
| ToC, Chapter 12 | Course Calendar |
(C) 2005, Doug Davis; all rights reserved